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Home/ Questions/Q 1100335
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T00:51:52+00:00 2026-05-17T00:51:52+00:00

So the issue is the user can either give input that is one int,

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So the issue is the user can either give input that is one int, or the user can give an input with three int. And it all depends on the first input. Little confusing so here is an example:

printf("Please enter input in this format: (-blackwhite | -color) colorvalue");

user inputs “-blackwhite 40” so I want to

scanf("%s %u", charArray, &int);

but user can also input “-color 254 254 254” then I would want to

scanf("%s %u %u %u", charArray, &int1, &int2, &int3);

How do I go about doing this? Basically verifying the data before I scan it into variables.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T00:51:52+00:00Added an answer on May 17, 2026 at 12:51 am

    Never use a naked (unbounded) %s in scanf unless you control totally the input data format (which you don’t here).

    Otherwise you open up your code to buffer overruns.

    What you should do is to fgets a line from stdin (since this provides buffer overrun protection) then simply sscanf the line.

    This has the added bonus that you can sscanf your longer four-argument format string and, if it fails, then try the two-argument one.

    Something like this:

    #include <stdio.h>
    
    int main (void) {
        char buffer[200];
        int i1, i2, i3, count;
    
        printf("Please enter input in format: (-blackwhite | -color) colorvalue: ");
        fflush (stdout);
        if (fgets (buffer, sizeof (buffer), stdin) != NULL) {
            if ((count = sscanf (buffer, " -color %d %d %d", &i1, &i2, &i3)) != 3)
                count = sscanf (buffer, " -blackwhite %d", &i1);
            switch (count) {
                case  1: printf ("blackwhite %d\n", i1);          break;
                case  3: printf ("color %d %d %d\n", i1, i2, i3); break;
                default: printf ("Huh?: %s\n", buffer);           break;
            }
        }
        return 0;
    }
    
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