Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
So, the partial view is a form, that is revealed via a jQuery show(). The form is submitted, and suppose a unique index is violated, for example, using the Post-Redirect-Get pattern I pass the errors via TempData back to the original view, which contains the partial view that is of course hidden again. Therefore the form’s errors/hints/original data is not visible.
What is the most efficient way of presenting/revealing this partial view’s form, with error message(s)?
Try not redirecting in case of error. If the ModelState is invalid simply return the same view. Then in the view you could display the form. If you want to continue using the Post-Redirect-Pattern you could store the ModelState into TempData as shown in this blog post and a nice implementation here.