Question

so this is my problems short version:

This works:

$query = mysql_query("SELECT * FROM `some_table` 
                     WHERE IF (LENGTH('$some_variable') > 0, `$other_variable` LIKE
                               '%$some_variable%' , 0)");

I get a result go through it with a while pack it all in an array and with json_encode send it back to my ajax file, where i list the result. And it works perfectly.

But when i ad one more thing to the query it just gives back empty, so this doesn’t work:

$query = mysql_query("SELECT * 
                      FROM `some_table` 
                      WHERE `something` = `some_other_thing` AND 
                          IF (LENGTH('$some_variable') > 0, `$other_variable` 
                               LIKE '%$some_variable%' , 0)");

So with that AND things just don’t work, but only whit ajax, i mean if i simply print the array out php works superbly.

Thanks in advance.

This is the rest of my php

while ($value = mysql_fetch_array($query)) {

$result[] = array
            (       
                gyarto => $value['gyarto'],
                termekcsalad => $value['termekcsalad'],
                kiszereles => $value['kiszereles']
            );
}

echo json_encode($result);

and my jquery:

$.ajax({
                    url:"updates/isu.php",
                    type:"POST",
                    data: form,
                    dataType: "json",
                    success: function(data) {


                    $.each(data, function(i)                            
                    {
                       $("#result table").append('<tr><td>'+data[i].gyarto+' '+data[i].termekcsalad+' '+data[i].kiszereles+'</td></tr>');

                    }); 

                }
            });

        });

Answer 1

I think you are mixing php language in a mysql query.

Try:

$query = mysql_query("SELECT * FROMsome_table WHEREsomething=some_other_thing AND  (LENGTH('$some_variable') > 0 AND '$other_variable` LIKE '%$some_variable%')");  

Also here is an exemple on how to use the mysql_fetch_array

mysql_connect("localhost", "mysql_user", "mysql_password") or
    die("Could not connect: " . mysql_error());
mysql_select_db("mydb");

$result = mysql_query("SELECT id, name FROM mytable");

while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    printf("ID: %s  Name: %s", $row["id"], $row["name"]);
}

mysql_free_result($result);