Question

So, this is what I thought would work:

Math.max($j.map($j.makeArray($j(".rl_shell")), function(val, i){
    $j(val).width();
}));

breakdown:

$j.isArray($j.makeArray($j(".rl_shell"))) 

returns true

and when I do just

$j.map($j.makeArray($j(".rl_shell")), function(val, i){
        $j(val).width();
    })

I get an empty array ([]) as a result.

$j(".rl_shell")

returns [div, div]

so, I’m guessing, that I’m using map wrong, but I used the syntax here:
http://api.jquery.com/jQuery.map/ so I’m not exactly sure what the deal is.

EDIT:

as per a couple of the answer’s suggestions, I’ve come up with this:

$j.map($j.makeArray($j(".rl_shell")), function(val, i){
    return $j(val).width();
});

which returns [0,950]

but when I add Math.max around it, I get NaN =/

Answer 1

Are you wanting to get the widest of all selected elements?

Math.max.apply(Math, $('selector').map(function(){ 
    return $(this).width(); 
}).get());