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Home/ Questions/Q 7796061
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:15:20+00:00 2026-06-01T23:15:20+00:00

So this is what I’m trying to do.. $sql=SELECT * FROM `members; while($rew =

  • 0

So this is what I’m trying to do..

$sql="SELECT * FROM `members";
while($rew = mysql_fetch_array($sql)){
    $var[] =",'".$rew['username']."'";
}
print_r ($var)

So I get the result:

Array ( [0] => ",'John'", [1] => ",'Mason'", [2] => ",'Greg'", [3] => ",'Paul'" )

So now I want the variable to display all results when I echo. For example:

<?php echo $var[1] ?>

And the result will be just ,'Mason'.

How do I get it so that I can echo $var[*] and get all the results. “John,Mason,Greg,Paul”.

I have been trying to figure this out for a very long time and is getting very frustrating for me. Can someone please help me.

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  1. Editorial Team
    Editorial Team
    2026-06-01T23:15:21+00:00Added an answer on June 1, 2026 at 11:15 pm

    Use PHP’s implode function.

    <?php echo implode(",", $var) ?>
    

    And change your loop code to:

    $var[] = $rew['username'];
    
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