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Home/ Questions/Q 615479
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:13:29+00:00 2026-05-13T18:13:29+00:00

So, this question has been asked before, but I wanted a question with some

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So, this question has been asked before, but I wanted a question with some of those key words in the title.

The issue is simple: How can I have a templated class, such that for each instance of the template – but not each instance of the class – there is a unique, numerical identifier?

That is, a way to differentiate:

foo<int> f1;
foo<char> f2;
classID(f1) != classID(f2);

but,

foo<int> f3;
foo<int> f4;
classID(f3) == classID(f4);

Related to:

in C++, how to use a singleton to ensure that each class has a unique integral ID?

Assigning Unique Numerical Identifiers to Instances of a Templated Class

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:13:30+00:00Added an answer on May 13, 2026 at 6:13 pm
    template<class T>
    class Base
    {
    public:
        static void classID(){}
    private:
        T* t;
    };
    
    int main()
    {
        Base<int> foo;
        Base<int> foo2;
        Base<char> foo3;
    
        /*
        unsigned int i  = reinterpret_cast<unsigned int>(Base<int>::classID);
        unsigned int ii = reinterpret_cast<unsigned int>(Base<char>::classID);
        unsigned int iii = reinterpret_cast<unsigned int>(Base<int>::classID);
        /*/
        unsigned int i  = reinterpret_cast<unsigned int>(foo.classID);
        unsigned int ii  = reinterpret_cast<unsigned int>(foo2.classID);
        unsigned int iii  = reinterpret_cast<unsigned int>(foo3.classID);
        //*/
    
        return ((i != ii) + (i <= ii) + (i >= ii)) == 2;
    }
    

    That’s how! It’s lightweight, super easy, and doesn’t use RTTI, although it uses the ridiculously unsafe reinterpret_cast.

    Although, maybe I’m missing something?

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