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Home/ Questions/Q 7732807
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:49:25+00:00 2026-06-01T06:49:25+00:00

So what I’m trying to do is create a live friends search. To do

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So what I’m trying to do is create a live friends search. To do this I need an array of names for AJAX to search through.

Heres my while loop.

if($_REQUEST['D'] == 'viewfriends') {
    $FREINDS = array();
    $FRIENDS_QUERY = "SELECT * FROM `FRIENDS` WHERE `USER` = '{$Modules['User']->Username}' AND `STATUS` = 'accepted' ORDER BY `ID` Limit 10 ;";
    $FRIENDS_RESULT = mysql_query($FRIENDS_QUERY);
    if(mysql_num_rows($FRIENDS_RESULT) > 0) {
        while($FRIENDS_ROW = mysql_fetch_assoc($FRIENDS_RESULT)) {
            $sql = "SELECT * FROM `USERS` WHERE `USERNAME` = '{$FRIENDS_ROW['FRIEND']}' ;";
            $REQUEST_ROW = mysql_fetch_assoc(mysql_query($sql));
            $FRIENDS = $REQUEST_ROW['USERNAME'];
        }
    echo json_encode($FRIENDS);
    } else {
        echo'<div class="update status">Sorry, You have no friends at this time. sadface.</div>';   
    }
}

I put the echo $FRIENDS in there as a test, right now it doesn’t display anything. Where did I derp?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:49:27+00:00Added an answer on June 1, 2026 at 6:49 am

    try this:

    if($_REQUEST['D'] == 'viewfriends') {
        $FRIENDS = array();
        $USERNAME = $Modules['User']->Username;
        $SQL_QUERY = "SELECT F.*, U.* FROM FRIENDS AS F LEFT JOIN USER AS U ON F.USER = U.USERNAME WHERE F.USERNAME = '{$USERNAME}' AND STATUS = 'accepted' ORDER BY F.ID LIMIT 10";
        $RESULTS = mysql_query($SQL_QUERY);
        if(mysql_num_rows($RESULTS) > 0) {
            while($ROW = mysql_fetch_assoc($RESULTS)) {           
                $FRIENDS[] = $ROW['USERNAME'];
            }
            echo json_encode($FRIENDS);
        } else {
            echo'<div class="update status">Sorry, You have no friends at this time. sadface.</div>';   
        }
    }
    

     $FRIENDS[] = $REQUEST_ROW['USERNAME'];
    

    then print_r($FRIENDS); echo will output array you need to loop the array or echo json_encode($FRIENDS); to see something

    also are you sure that USERNAME is uppercase and not just username in lowercase lowercase as well as for the table name.

    also i think you can use a JOIN clause instead of making to SQL requests

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