Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6559151
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T13:17:15+00:00 2026-05-25T13:17:15+00:00

So when I take pictures they get saved to DCIM/Camera/ directory. I need to

  • 0

So when I take pictures they get saved to DCIM/Camera/ directory. I need to retrieve the pictures after taken to send via email.

How can I get the name of the last picture taken? (Or adjust my current code to customize the file name.)

Here’s the code for taking the picture:

function capturePhoto(id) { 
navigator.camera.getPicture(onSuccess, onFail, { quality: 20,
destinationType: Camera.DestinationType.FILE_URI });    

function onSuccess(imageURI) {  
var image = document.getElementById(id);  

image.style.display = 'block'; 
image.src = imageURI;  

}   

function onFail(message) {  
alert('Failed because: ' + message);  
}  
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T13:17:16+00:00Added an answer on May 25, 2026 at 1:17 pm

    Here’s the answer to my question. You have to be running Phonegap 1.0. This will put the picture where ever you want it and name it what ever you want. So then you can reference by filename and do what ever you want with it.

    var gotFileEntry = function(fileEntry) { 
                console.log("got image file entry: " + fileEntry.fullPath); 
                var gotFileSystem = function(fileSystem){ 
                    // copy the file 
                    fileEntry.moveTo(fileSystem.root, "pic.jpg", null, null); 
               }; 
                // get file system to copy or move image file to 
                window.requestFileSystem(LocalFileSystem.PERSISTENT, 0, gotFileSystem, fsFail); 
            }; 
            //resolve file system for image  
            window.resolveLocalFileSystemURI(imageURI, gotFileEntry, fsFail); 
    }
    
    // file system fail 
        function fsFail(error) { 
            console.log("failed with error code: " + error.code); 
        }; 
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

When I take pictures using android.hardware.camera and I save them to the following location
I am working on an application, where i take pictures from a camera and
I have a camera view where the user can take pictures and do whatever
I want to help user to take their pictures with a plugged in video
I made small program to divide large pictures and take part of them. When
I take the picture with camera.take picture and getting those data in on Picture
I am working on the camera code in android to take picture and save
I am using LinkSprite JPEG Color Camera to take picture. I am getting hex
Is there a possibility to take a picture using phone's camera without user interaction?
I'm writing an application which have to take a picture and send it to

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.