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Home/ Questions/Q 8242489
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T21:11:10+00:00 2026-06-07T21:11:10+00:00

So when i write this chunk of code separately, it works fine but when

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So when i write this chunk of code separately, it works fine but when i combine them together it give me typeError. Why is this happen? I don’t get it when i wrote them separately it works fine. thanks in advance 🙂

def printOutput(start, end, makeList):

  if start == end == None:

      return

  else:

      print start, end

      with open('OUT'+ID+'.txt','w') as outputFile:#file for result output
          for inRange in makeList[(start-1):(end-1)]:
              outputFile.write(inRange)
          with open(outputFile) as file:
              text = outputFile.read()
      with open('F'+ID+'.txt', 'w') as file:
        file.write(textwrap.fill(text, width=6))
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T21:11:12+00:00Added an answer on June 7, 2026 at 9:11 pm

    Your problem is at this line:

     with open(outputFile) as file:
    

    outputFile is a file object (which is already open). The open function wants a string (or something like it) which is the name of a file to open.

    If you want to get the text back, you can always outputFile.seek(0) and then outputFile.read() again. (Of course, you’ll have to open in r+ mode for this to work.)

    Perhaps an even better way to do this would be:

    with open('OUT'+ID+'.txt','w') as outputFile:#file for result output
        text=''.join(makeList[(start-1):(end-1)])
        outputFile.write(text)
    with open('F'+ID+'.txt', 'w') as ff:
        ff.write(textwrap.fill(text, width=6)) #Version of above file with text wrapped to 6 chars.
    

    EDIT

    This should work:

    def printOutput(start, end, makeList):
        if start == end == None:
            return
        else:
            print start, end
    
            with open('OUT'+ID+'.txt','w') as outputFile:#file for result output
                text=''.join(makeList[(start-1):(end-1)])
                outputFile.write(text)
            with open('F'+ID+'.txt', 'w') as ff:
                ff.write(textwrap.fill(text, width=6)) #Version of above file with text wrapped to 6 chars.
    
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