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Home/ Questions/Q 8389997
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:52:18+00:00 2026-06-09T18:52:18+00:00

So you find an exception in your logs: Execution of JMS message listener failed,

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So you find an exception in your logs:

Execution of JMS message listener failed, and no ErrorHandler has been set.
com.company.eq.mo.app.exception.DefaultMessageListenerException: Failed to handle message.; nested exception is com.company.eq.mo.app.exception.DefaultMessageListenerException: This message does not contain a recognised java object; nested exception is javax.jms.MessageFormatException: MQJMS1061: Unable to deserialize object the class name to find out anymore info about the message:

The message is Deserialisable and you can’t get and print the object out at runtime:

    Object object = ((ObjectMessage) message).getObject();
                object.getClass();

Because it does not exist in your class path.

Is there any other way of getting the class/object name?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:52:19+00:00Added an answer on June 9, 2026 at 6:52 pm

    You can implement your own parser for Java Object Serialization Stream Protocol, but for most practical purposes you do need to have all serialized classes available in the class path.

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