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Home/ Questions/Q 908687
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:45:24+00:00 2026-05-15T16:45:24+00:00

Somebody generalized the statement Temporaries are rvalues . I said no and gave him

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Somebody generalized the statement “Temporaries are rvalues“. I said “no” and gave him the following example

 double k=3;

 double& foo()
 {
    return k;
 }

 int main()
 {

     foo()=3; //foo() creates a temporary which is an lvalue
 }

Is my interpretation correct?

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:45:24+00:00Added an answer on May 15, 2026 at 4:45 pm

    Temporaries and rvalues are different (but related) concepts. Being temporary is a property of an object. Examples of objects that aren’t tempory are local objects, global objects and dynamically created objects.

    Being an rvalue is a property of an expression. The opposite of rvalues are lvalues such as names or dereferenced pointers. The statement “Temporaries are rvalues” is meaningless. Here is the relationsip between rvalues and temporary objects:

    An rvalue is an expression whose evaluation creates a temporary object which is destroyed at the end of the full-expression that lexically contains the rvalue.

    Note that lvalues can also denote temporary objects!

    void blah(const std::string& s);
    
    blah(std::string("test"));
    

    Inside the function blah, the lvalue s denotes the temporary object created by evaluating the expression std::string("test").

    Your comment “references are lvalues” is also meaningless. A reference is not an expression and thus cannot be an lvalue. What you really mean is:

    The expression function() is an lvalue if the function returns a reference.

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