Question

Somebody posted me this code to me with a problem I had:

         $('#txtWeight').each( function() {

 var $this = $(this);
 var $weightText = $("<input type='text' class='txtWeightRow' maxlength='5' onkeypress='return isNumberKey(event)'/>").attr('name',$this.attr('name'))
                 .attr('value',$this.val())

$weight.append($weightText).append('%');

});

What I want to know is what does .attr('name',$this.attr('name')). Am I not going to be able to call my input to whatever name I want it to. Does this link the “name” with a previous “name”?

Thanks

Answer 1

Supplying a second argument to the attr function sets the attribute to this value.

So your example is setting the name attribute of all inputs with name txtWeightRow to the value of the name attribute of whatever $this is.

In order to see what $this is you’d have to supply some more context.