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Home/ Questions/Q 541349
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:20:04+00:00 2026-05-13T10:20:04+00:00

Sometimes in my application there are many elements loading so I want to show

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Sometimes in my application there are many elements loading so I want to show the typical AJAX spinner above the control (or DOM node) with it disabled.

What is the easiest/best way to do that?

Ideally I would like to:

$("#myelement").loading();
$("#myelement").finishloading();

Or even better being able to do AJAX requests directly with the element:

$("#myelement").post(url, params, myfunction);

Being #myelement a regular node or form input.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:20:04+00:00Added an answer on May 13, 2026 at 10:20 am

    Since you’re already using jQuery, you may want to look into BlockUI in conjunction with Darin Dimitrov’s answer. I haven’t used it yet myself as I just came across this today, but it looks decent.

    If you’re writing a semi-large-ish application and anticipate making many AJAX calls from different places in your code, I would suggest that you either add a layer of abstraction over $.ajax, or create a helper function to avoid having boiler plate for your UI indicator all over the place. This will help you out a lot should you ever need to change your indicator.

    Abstraction method

    var ajax = function(options) {
        $.ajax($.extend(
            {
                beforeSend: function() {
                    $.blockUI();
                },
                complete: function() {
                    $.unblockUI();
                }
            }, 
            options
        ));
    };
    
    ajax({
        url: 'script.cgi',
        type: 'POST',
        success: function(result) {
            // todo: do something with the result
    });
    

    Helper method

    var ajaxSettings = function(options) {
        return $.extend(
            {
                beforeSend: function() {
                    $.blockUI();
                },
                complete: function() {
                    $.unblockUI();
                }
            }, 
            options
        );
    };
    
    $.ajax(ajaxSettings({
        url: 'script.cgi',
        type: 'POST',
        success: function(result) {
            // todo: do something with the result
        }
    }));
    

    Also, I wouldn’t suggest overwriting the $.ajax method itself.

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