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Home/ Questions/Q 202077
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:15:19+00:00 2026-05-11T17:15:19+00:00

Somewhere I was reading that – regarding low memory warnings and giving up an

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Somewhere I was reading that – regarding low memory warnings and giving up an non-visible view with all it’s subviews (= a whole nib, I think), you should do that:

-(void)dealloc {
    [anView release], anView = nil;
    [someImageView release], someImageView = nil;

    [super dealloc];
}

rather than

-(void)dealloc {
    [anView release];
    [someImageView release];

    [super dealloc];
}

What’s the reason for grounding those pointers to nil (= “no object”), after I call release? Let me guess: Some other method could have -retain’ed the view for some reason (anyone any example for when this could happen?), then the didReceiveMemoryWarning thing happens, and you release a whole nib+view that’s currently not visible (i.e. in a multiview-app). As soon as the user wants to see that view again, you would quickly load the nib again and then: It loads all views, connects the outlets, and BANG! Your other retain’ed view’s are hanging now without any pointer somewhere lonely in the memory brick, causing a fat and deep memory leak until your app crashes.

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:15:20+00:00Added an answer on May 11, 2026 at 5:15 pm

    rather than doing the expicit release and set to nil, if your accessors have properties associated with them yoc and do the following as a more concise method:

    - (void) dealloc
    {
        self.retainedProperty1 = nil;
        self.retainedProperty2 = nil;
        self.copiedProperty = nil;
        self.assignedProperty = nil;
    }
    

    this way you can have code that has less repetition since the synthesized code will take care of your releases for you.

    Edit: i should point out that your properties can’t be readonly or else you get compiler errors for obvious reasons 🙂

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