Question

Sorry for the probably dumb question, but i wanted to practice loops a bit and came out with this idea.Basically it ask you to enter or not in a loop and when you’re in, it ask you for something to do.The problem is that just after i enter the loop it prints two times the printf string before passing to the scanf one and waiting for an input. I can’t figure it out.
All help is welcome! Here’s the code:

#include <stdio.h>

int main() 
{
    char check = 'a';
    char int_check = 'a';
    int b = 0;
    printf("want to go in? [y or n]\n");
    scanf("%c",&check);
    if ( check == 'y') {
        while (1){
            printf("Waiting: \n");
            scanf("%c",&int_check);
            if ( int_check == 'q'){
                printf("You're out, bye!\n");
                break;
            };
        };
    } else if ( check == 'n'){
        printf("You're not in, see ya!\n");
    }else {
        printf("Please, type 'y' or 'n'\n");
    };
    return 0;
}

Answer 1

If you input onto a terminal the following:

x

The first loop will see an x

The second loop will see a newline character.

The easiest way to work around this is to use sscanf and getline.