Question

Sorry for the simple question, but how could I create the C-function with undefined number of parameters such as

int printf ( const char * format, ... ).

I would like to create function to use it as wrapper for printk:

void my_printk( const char * format, ...)
{
    printk("my log:");
    printk(format, ...);
    printk("\n");
}

Thanks

Answer 1

You’re close. Have a look here: http://publications.gbdirect.co.uk/c_book/chapter9/stdarg.html

int f(int, ... );

int f(int, ... ) {
        .
        .
        .
}

int g() {
        f(1,2,3);
}