Question

sorry Friends i did a mistake. I have did this mistake again. am really very sorry.

this is the Issue.

I have a time range like

int Starttime = 2 which mean(02:00)
int enttime =  8 which mean(08:00)

i want time in sum of bits,
example

     00:00 1  
     01:00 2    
     02:00 4  -----
     03:00 8   R
     04:00 16  a
     05:00 32  n
     06:00 64  g
     07:00 128 e
     08:00 256 -----

and soo on till 23:00

so i need totalRange = 256+128+64+32+16+8+4 ;

it should be like this
sorry again.

Thanks

Answer 1

The table indicates that you want to map the hour value of a time to an integer value using this function:

int value = (int) Math.pow(2, hourValue);

or, in other words, 00:00h will map to 2⁰, 12:00h to 2¹² and so on.

Now if you have need the sum of start and endtime, you can simple use the function from above and add the values:

int totalrange = (int) Math.pow(2, starttime) + (int) Math.pow(2, endtime);

Now if you have starttime=2 and endtime=23, this will give a result (written in binary):

01000000 00000000 00000100

---

shamelessly adapting polygenelubricants much faster solution:

int totalrange = (1 << starttime) + (1 << endtime);

This works, because 2ⁱ is equal to (1 << i).