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Asked: 2026-06-10T15:12:32+00:00

Sorry, I am just starting with all this EJB, JSF and JAX-RS stuff and

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Sorry, I am just starting with all this EJB, JSF and JAX-RS stuff and need your help now.
I have created a JAX-RS Resource class, which works very well and implements @GET, @PUT, etc. Methods.

In the same project I now created a JSF page with the according BackBean. This Backbean should talk to the REST interface. While testing, I hardcoded the URI of the REST Interface into the bean, but of course I would like to get the URI programmaticly. I tried with a @Produces method and injection, but I always get an IllegalStateException. I think this has to do with contexts, but I actually do not have the understandning to solve it.

My REST Resource:

@Path("task")
@ManagedBean
@RequestScoped
public class TaskResource {

@Context
private UriInfo context;

@Inject TaskLifecycle lc;

public TaskResource() {
}

@GET
@Path("{id}")
public Response getTask(@PathParam("id") String id)  { ... etc.

My Backbean:

@ApplicationScoped
@LocalBean
@Named("tmmlWrapper")
public class TmmlTaskWrapperBean implements Serializable {

// Here another ManagedBean is injected, which works fine!
@Inject TaskLifecycle       lc;

and finally my JSF Page:

<?xml version='1.0' encoding='UTF-8' ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org
/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
    xmlns:h="http://java.sun.com/jsf/html"
    xmlns:f="http://java.sun.com/jsf/core">
<h:head>
    <title>Tasklist</title>
</h:head>
<h:body>
    <h:form>
        <h:outputLabel ><h3>Tasklist:</h3></h:outputLabel>

        <h:dataTable value="#{tmmlWrapper.taskList}" var="tl">

        <h:column>

            <f:facet name="header">ID</f:facet>
            #{tl.id}

        </h:column> ... and so on ... etc.

My question:
How can my BackBean get the URI of the REST resource (ex. “http://exampledomain:8080/as&#8221;)?
Any help is welcome!

Cheers,
Joern

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1 Answer

  1. Editorial Team

    You’ll first need to get access to the underlying servlet container (assumed to one, instead of a portlet container) produced HttpServletRequest object. Use the FacesContext object to access the HttpServletRequest object in the following manner:

    HttpServletRequest origRequest = (HttpServletRequest)FacesContext.getExternalContext().getRequest();

    The HttpServletRequest class provides several utility methods to obtain a near representation of the original request:

    • getRequestURL(), which provides the original request sans the query string
    • getScheme, getServerName, getServerPort, getContextPath, getServletPath, getPathInfo and getQueryString all of whose outputs can be combined in sequence to obtain the original request. You may have to omit the latter invocations if you want a lesser fragment of the URL.
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