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Home/ Questions/Q 517877
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Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T07:52:46+00:00 2026-05-13T07:52:46+00:00

Sorry if my title is hard to understand. Let me explain. To use this

  • 0

Sorry if my title is hard to understand. Let me explain.

To use this example of my structure:

Array
(
[2] => Array
    (
        [0] => stdClass Object
            (
                [category_id] => 2
                [category_name] => women
                [project_id] => 1
                [project_name] => Balloons
            )

    )

[1] => Array
    (
        [0] => stdClass Object
            (
                [category_id] => 1
                [category_name] => men
                [project_id] => 2
                [project_name] => Cars
            )

        [1] => stdClass Object
            (
                [category_id] => 1
                [category_name] => men
                [project_id] => 3
                [project_name] => Houses
            )

    )

Then once i have that, i send it out to be eval’d by javascript(which is successful). Console.log does in fact shows that’s my eval’d json is in fact now an object.

Now, If i console.log(myArray[2]), it will show it as an array that contains another array. Which is also correct

BUT!.. if i try to do this:

for (item in myArray[2]) {
...
}

or this:

newVar = myArray[2]
for (item in newVar) {
...
}

“item” doesn’t contain the array as it should. it contains a string equal the sub arrays’ key. Which in this case is “0”

What am I missing here guys? 🙁

Thanks for the help!

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:52:47+00:00Added an answer on May 13, 2026 at 7:52 am

    You already said what the problem was: “item” doesn’t contain the array… it contains a string equal the sub arrays’ key. So, you just need to use that key:

    var subarray;
    for (var i in myArray) {
        subarray = myArray[i];
        for (var j in subarray) {
            ... // do stuff with subarray[j]
        }
    }
    
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