Question

Sorry if this is a bit of a silly question.

Here is my code:

#include<iostream>
using namespace std;

int main()
{
  int columns, rows;
  char **map;

  cin>>columns;
  cin>>rows;

  /*creats array of pointers rows tall*/
  map = new char*[rows];

  /*creats array of chars columns tall*/
  for(int i=0; i<rows; i++)
    map[i] = new char[columns];

  //populate map with input
  map[0][0] = cin.get();
  for(int j=0; j<rows; j++)
    for(int i=0; i<columns; i++)
    {
      if (cin.peek() == '\n')
        cin.ignore(256, '\n');
      else
        map[j][i] = cin.get();
    }


  //DISPLAY
  cout<<endl;
  for(int j=0; j<rows; j++)
  {
    for(int i=0; i<columns; i++)
    {
      cout<<map[j][i];
    }
  }
  return 0;
}

The user will input something like:

7 4
#######
#S#   #
#   #E#
#######

and I would like to output it. However mine comes out like:

#######
#S#    
##   #
E#####

Any thoughts?

Answer 1

First for loop:

  //populate map with input

  for(int j=0; j<rows; j++)
  {
    cin.get();
    for(int i=0; i<columns; i++)
    {
      if (cin.peek() == '\n')
        cin.ignore(256, '\n');
      else
        map[j][i] = cin.get();
    }
  }

And add the new line to output:

  //DISPLAY
  cout<<endl;
  for(int j=0; j<rows; j++)
  {
    for(int i=0; i<columns; i++)
    {
      cout<<map[j][i];
    }
    cout << endl;
  }

Always make sure you get the trailing enter out of the input stream before reading it again.