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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T18:02:28+00:00 2026-05-11T18:02:28+00:00

Sorry I’m really bad at regexes, I finally hacked osmething to work in ruby.

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Sorry I’m really bad at regexes, I finally hacked osmething to work in ruby. I’d appreciate if someone can instruct the proper way of how to do this:

I basically wanted to remove all \n when it appears within ul tags.

while body =~ /<ul>.*(\n+).*<\/ul>/m
  body =~ /<ul>(.+)<\/ul>/m
  body.gsub!(
    /<ul>(.+)<\/ul>/m,
    "<ul>#{$1.gsub("\n","")}</ul>" )
end

The 2nd line took me forever to figure out, since the $1 was from the while loop, not actually from the gsub statement.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-11T18:02:28+00:00Added an answer on May 11, 2026 at 6:02 pm

    With regexp’s TIMTOWTDI but here’s one shorter attempt:

    body.gsub!(/<ul>.*?<\/ul>/m) {|m| m.tr("\n",'') }
    

    Basically find (non-greedily) all ul-tags and replace them with all linefeeds removed (check RDoc for String.gsub! and String.tr)

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