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Home/ Questions/Q 4013652
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T09:23:54+00:00 2026-05-20T09:23:54+00:00

Sorry this is basic, but I’m new to Python and Django. I have a

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Sorry this is basic, but I’m new to Python and Django.

I have a list of users who have performed an action that is being saved in a separate table. I want to show a list of these users, sorted by how many times they’ve taken the other action.

I understand how to get the counts:

users = User.objects.all()
for user in users:
    print user.action_set.count()

And I understand how to show the counts in my template:

{% for user in users %}
    {{ user.action_set.count }}
{% endfor %}

But I’m not sure how to have it sort the users by the count of the action set.

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:23:54+00:00Added an answer on May 20, 2026 at 9:23 am

    Annotate / Aggregation
    http://docs.djangoproject.com/en/dev/topics/db/aggregation/

    from django.db.models import Count
    users = User.objects.annotate(action_count=Count('action')).order_by('action_count')
    # note that this also saves your extra query PER user object.
    
    {% for user in users %}
       {{ user.action_count }}
    {% endfor %}
    

    For future reference, if you couldn’t sort by the DB, you can python sort any list…

    my_list.sort(key=lambda x: x[2])
    
    my_list.sort(key=lambda x: x.method())
    

    Very useful.

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