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Home/ Questions/Q 7820647
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T07:22:44+00:00 2026-06-02T07:22:44+00:00

Sorry to ask such a basic question. Say, I have two inputs. The first

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Sorry to ask such a basic question. Say, I have two inputs. The first one is always visible, while the second shows up only when the first one’s value is less than 0. I tried to use .change to implement this activity, however it does not work. So can anyone give me some suggestions?
Thanks in advance.

HTML code:

<table>
<tr><th><label for="id_first">First input:</label></th><td><input type="text" name="First input" id="id_first" /></td></tr>
<tr><th><label for="id_second">Second input:</label></th><td><input type="text" name="First input" id="id_second" />
</td>
</tr>
</table>

jQuery code

<script type="text/javascript" src=" ../stylesheets/jQuery-1.7.2.js"></script> 

<script>
$(document).ready(function() {
    $('#id_second').closest('tr').hide();
    $('#id_first').change(function() {    
    if ($(this).val() <0){
        $('#id_second').show()}    
    else{
        }
    });​​ 
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  1. Editorial Team
    Editorial Team
    2026-06-02T07:22:46+00:00Added an answer on June 2, 2026 at 7:22 am

    your jquery code should be as below. You had a syntax error. You did not close the change function, and you have to show “tr”, not just the input element

    $(document).ready(function() {
        $('#id_second').closest('tr').hide();
        $('#id_first').change(function() {    
            if ($(this).val() <0){
                $('#id_second').closest("tr").show()
            }    
            else{
            }
        });
    });​​ 
    
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