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Home/ Questions/Q 8570515
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T18:34:33+00:00 2026-06-11T18:34:33+00:00

Sort of like this: function getfoo() { var foo = ; $.get(foofile.html, function (data)

  • 0

Sort of like this:

function getfoo() {
  var foo = "";
  $.get("foofile.html", function (data) {
    foo = data;
  });
  return foo;
}

But then since the script is asynchronous, it will return “”. That’s obviously not what I want.

So then I tried this:

function getfoo() {
  var foo = "";
  $.get("foofile.html", function (data) {
    foo = data;
  });
  for (;;) {
    if (foo != "") {
      return foo;
      break;
    }
  }
}

And I expected that to work, but it didn’t. Why not? And can someone suggest a solution?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T18:34:35+00:00Added an answer on June 11, 2026 at 6:34 pm

    You should use a callback pass to the function and let it deal your data.

    function getfoo(callback) {
      var foo = "";
      $.get("foofile.html", function (data) {
        callback(data);
        // do some other things
        // ...
      });
    }
    
    getfoo(function(data) {
       console.log(data);
    });
    
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