Question

Source file

<?xml version="1.0" encoding="UTF-8"?>
<!--It will contain more data, just given few here-->
<Food>
<Menu>Item1</Menu>
</Food>

Require output:

<?xml version="1.0" encoding="UTF-8"?>
<Detail>
<SubDetail>
<Food>
<Menu>Item1</Menu>
</Food>
</SubDetail>
</Detail>

I would like to add the source xml(contains more than 200 lines) in between Detail and SubDetails. Could you please tell me how to write the xslt.

Answer 1

Just stating the obvious: Instead of explicit recursive copying, you could also use <xsl:copy-of> command if you want to copy the selected node and all of its contents. Copying the whole input document inside <Detail> and <SubDetail> wrapper element can be done with one xsl command within one template. Your final use case is probably more complex, but the logic is the same.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output indent="yes" omit-xml-declaration="no" encoding="UTF-8"/>

<xsl:template match="/">
    <Detail>
        <SubDetail>
            <xsl:copy-of select="."/>
        </SubDetail>
    </Detail>
</xsl:template>

</xsl:stylesheet>