Specifically, what does the ($c1 & 0x03) << 4 do?
Is 0x03 hex notation?
Specifically, what does the ($c1 & 0x03) << 4 do? Is 0x03 hex notation?
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It does mean first operation do logically AND with HEX value 0x03(that is 3 in HEX or (0011) in Binary).and then left Shift 4 places.example
let u have $c = 34.
then first it performs $c & 3 which is (100010 BITWISE AND 000011) which Gives you (000010)
and then It shifts 4 digit on left position and restore new value in $c i.e (100000) or 32 in decimal.
Hope it is Helpful.
Thanks