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Home/ Questions/Q 8951467
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T13:40:14+00:00 2026-06-15T13:40:14+00:00

Spring java- quartz schedular application I want to load .property file dynamically passed throw

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Spring java- quartz schedular application

I want to load .property file dynamically passed throw program parameter instead of context:property-placeholder in spring context, how can i achieve this task, any help appreciated…

I am manually loading and refreshing spring context from main java file as illustrate by following code.

SpringUtil_1.loadSpringConfig();
rootContext = new ClassPathXmlApplicationContext();
rootContext.setConfigLocation("abc-configuration.xml");
rootContext.refresh();

In spring configuration i have context property place holder as follows which i want to from code.

<context:property-placeholder location="classpath:lnRuntime.properties"/>

i am using place holders in spring context and java file using spring EL as follows

<bean id="dataSource" 
class="org.springframework.jdbc.datasource.SingleConnectionDataSource">
        <property name="driverClassName" value="net.sourceforge.jtds.jdbcx.JtdsDataSource"/>
        <property name="url" value="${dataSource.url}"/>
    </bean>

and in java i am accesing as follows

private @Value("${dz.host}") String dzHost;
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  1. Editorial Team
    Editorial Team
    2026-06-15T13:40:15+00:00Added an answer on June 15, 2026 at 1:40 pm

    Found answer

    @Bean
    public static PropertySourcesPlaceholderConfigurer properties(){
      PropertySourcesPlaceholderConfigurer pspc =
       new PropertySourcesPlaceholderConfigurer();
      Resource[] resources = new ClassPathResource[ ]
       { new ClassPathResource( "foo.properties" ) };
      pspc.setLocations( resources );
      //pspc.setIgnoreUnresolvablePlaceholders( true );
      return pspc;
    }
    

    Resoruces http://www.baeldung.com/2012/02/06/properties-with-spring/#byhandnew

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