Question

SQL Code:

SELECT id, album_date AS timestamp, CONCAT((SELECT detail_value
FROM people_db.user_details_tbl WHERE detail_field = 'first_name' AND user_id = pictures_db.albums.owner), ' uploaded pictures!') AS title_html 
FROM pictures_db.albums 
WHERE id IN 
(SELECT DISTINCT(album_id) 
FROM pictures_db.album_pics 
WHERE pic_id IN 
    (SELECT DISTINCT(picture_id) 
    FROM pictures_db.picture_access_tbl 
    WHERE grantee_group_id IN 
        (SELECT group_id 
        FROM people_db.group_membership_tbl
        WHERE member_id = '2'
        )
     )
);

PHP Code:

$albums_sql = mysql_query("SELECT id, album_date AS timestamp, CONCAT((SELECT detail_value 
    FROM people_db.user_details_tbl 
    WHERE detail_field = 'first_name' AND user_id = pictures_db.albums.owner), ' uploaded pictures!') AS title_html 
    FROM pictures_db.albums 
    WHERE id IN (
          SELECT DISTINCT(album_id) 
          FROM pictures_db.album_pics 
          WHERE pic_id IN (
              SELECT DISTINCT(picture_id) 
              FROM pictures_db.picture_access_tbl 
              WHERE grantee_group_id IN (
                  SELECT group_id 
                  FROM people_db.group_membership_tbl 
                  WHERE member_id = '2'
                  )
               )
             )") or die(mysql_error());

When the PHP is run, the error is: Table ‘pictures_db.albums’ doesn’t exist

I tried executing as the same user, regranted all permissions, and even flushed privileges. Works in shell, not in PHP.
Any ideas?

Answer 1

The error message is quite clear: MySQL sees the database pictures_db but not the table albums.

That could be due to permissions, but you seem to have checked that thoroughly.

Another possible reason is that the connection string you’re using in PHP points to a different database instance than the one you’re using at the command line. Perhaps the connection string still points to a different environment, such as DEV but you’re in QA or points to an old test version of the database?