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Home/ Questions/Q 8129027
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T08:08:05+00:00 2026-06-06T08:08:05+00:00

$sql = SELECT * FROM cars WHERE COUNT(brand)=’4′; $results = mysql_query($sql); $rows = mysql_fetch_array($results);

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   $sql = "SELECT * FROM cars WHERE COUNT(brand)='4'";
   $results = mysql_query($sql);
   $rows = mysql_fetch_array($results);
   print_r($rows);

the table cars has these columns:

id brand     price
0  bmw
1  corvette
2  mercedes
3  bmw
4  bmw
5  toyota
6  bmw
7  honda
8  lotus

this is what I am trying to do, return from the table 'cars' every brand that has 4 different cars. In this example bmw has 4
4 different cars is 4 different rows with the same brand name.
so I am trying to echo the name of the brand where the total number of inventory is 4.
I hope I made sense, any help would be appreciated.

EDIT: I tried
SELECT * FROM cars LEFT JOIN users ON cars.user_id=users.user_id HAVING count(user_id) = 4 this is not working any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T08:08:09+00:00Added an answer on June 6, 2026 at 8:08 am
    SELECT brand FROM cars GROUP BY brand HAVING COUNT(brand) = 4
    

    For you edit:

    SELECT t1.brand, t2.email 
    FROM cars t1  
    LEFT JOIN users t2 ON t1.user_id = t2.user_id 
    GROUP BY t1.brand HAVING COUNT(t1.brand) = 4
    
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