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Home/ Questions/Q 6560571
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:28:38+00:00 2026-05-25T13:28:38+00:00

$SQL = SELECT * FROM `user_posts` WHERE (`post` LIKE ‘%@.$user.%’); For instance, if my

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    $SQL = "SELECT * FROM `user_posts` WHERE (`post` LIKE '%@".$user."%')";

For instance, if my username is @Jake, it will show any post that has @Jake in it. But it will also do for instance, @Jake11, it will also show. How can I fix this?

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:28:39+00:00Added an answer on May 25, 2026 at 1:28 pm

    You might consider using some sort of regular expression instead of LIKE '%...%'.

    An example might be:

    ... WHERE `post` REGEXP '@" . mysql_real_escape_string( $user ) . "[[:>:]]'"
    

    The [[:>:]] matches on a right word boundary. As pointed out by Bill Karwin, there’s no need for a left-hand boundary pattern in this case as there is an implied word boundary at the @ character. (Indeed, you can’t have a left-boundary to the left of a non-word character.)

    (I’m sure others will comment on your possible exposure to SQL injection attack too.)

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