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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:53:23+00:00 2026-05-13T12:53:23+00:00

SQL Server 2008 again. I have a primary key pt_id and a datetime column

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SQL Server 2008 again. I have a primary key pt_id and a datetime column order_dts for each id. I want to count the number of keys in each year from 1996-2008 and return eight results – a count for each year. For a single year

SELECT COUNT pm.pt_id AS '1996'
FROM dm.medications pm
WHERE (pm.order_dts BETWEEN '1/1/1996' and '12/31/1996')

works, but how I can I do all of the years without having to do something ridiculous like eight different queries?

Thank you!

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:53:23+00:00Added an answer on May 13, 2026 at 12:53 pm
    SELECT COUNT(*),  Year(pm.order_dts) as Year
    FROM dm.medications pm
    WHERE Year(pm.order_dts) between 1996 AND 2008
    group by Year(pm.order_dts)
    

    If you want it all in one row, you can do:

    SELECT 
        sum(case when Year(pm.order_dts) = 1996 then 1 end) as Count1996,
        sum(case when Year(pm.order_dts) = 1997 then 1 end) as Count1997,
        sum(case when Year(pm.order_dts) = 1998 then 1 end) as Count1998,
        sum(case when Year(pm.order_dts) = 1999 then 1 end) as Count1999,
        sum(case when Year(pm.order_dts) = 2000 then 1 end) as Count2000,
        sum(case when Year(pm.order_dts) = 2001 then 1 end) as Count2001,
        sum(case when Year(pm.order_dts) = 2002 then 1 end) as Count2002,
        sum(case when Year(pm.order_dts) = 2003 then 1 end) as Count2003,
        sum(case when Year(pm.order_dts) = 2004 then 1 end) as Count2004,
        sum(case when Year(pm.order_dts) = 2005 then 1 end) as Count2005,
        sum(case when Year(pm.order_dts) = 2006 then 1 end) as Count2006,
        sum(case when Year(pm.order_dts) = 2007 then 1 end) as Count2007,
        sum(case when Year(pm.order_dts) = 2008 then 1 end) as Count2008
    FROM dm.medications pm
    
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