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Home/ Questions/Q 1084137
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:31:27+00:00 2026-05-16T22:31:27+00:00

sqlite3 I have two tables. One contains some lists and the other contains each

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sqlite3

I have two tables. One contains some lists and the other contains each list’s items.

I want to create a select statement that grabs the rows in the lists table, but also creates a column which is a comma-delimited summary of the items in each list.

I have this working as follows:

select
    master._id as _id,
    master.name as name,
    master.created_on as created_on,
    group_concat(items.name, ', ')
from
    tablea master
join
    tableb items
on
    master._id = items.master_id
group by
    master._id

However, I would like to name the column returned by the group_concat as “summary” like so:

select
    master._id as _id,
    master.name as name,
    master.created_on as created_on,
    group_concat(items.name, ', ') as summary
from
    tablea master
join
    tableb items
on
    master._id = items.master_id
group by
    master._id

When I do this, I get an sql error:
“SQL error: near “summary”: syntax error

How can I achieve what I’m wanting to do?

I would also like to order the items in the group_concat alphabetically descending, but naming the column is my first priority.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:31:28+00:00Added an answer on May 16, 2026 at 10:31 pm

    “AS” is optional. However, both with and without “AS” works fine for me (using SQLite version 3.6.14.2):

    drop table tablea;
    drop table tableb;
    create table tablea(_id int, name varchar, created_on varchar);
    create table tableb(master_id int, name varchar);
    insert into tablea values(0, 'Hello', '2010');
    insert into tableb values(0, 'x');
    select
        master._id as _id,
        master.name as name,
        master.created_on as created_on,
        group_concat(items.name, ', ') as summary
    from
        tablea master
    join
        tableb items
    on
        master._id = items.master_id
    group by
        master._id
    
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