Question

start_date = '07_Nov_2011'
end_date = '10_Jan_2012'

I want to print all the intermediate dates in the same format:

day_month_year

If I can somehow convert start_date to date type I can do this:

sdate+timedelta(1)).strftime('%d_%b_%Y')

How do I convert it? Or is there a better way to do this?

Answer 1

You can use datetime.datetime.strptime(...) to do the conversion. Like this:

>>> datetime.datetime.strptime('07_Nov_2011', '%d_%b_%Y').date()
datetime.date(2011, 11, 7)

You can print all the intermediate dates with something like this:

>>> start_date = '07_Nov_2011'
>>> end_date = '10_Jan_2012'
>>> 
>>> first = datetime.datetime.strptime(start_date, '%d_%b_%Y')
>>> last = datetime.datetime.strptime(end_date, '%d_%b_%Y')
>>> for i in xrange((last-first).days):
...     print (first+datetime.timedelta(i)).strftime('%d_%b_%Y')
... 
07_Nov_2011
08_Nov_2011
09_Nov_2011
10_Nov_2011
11_Nov_2011

etc.