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Home/ Questions/Q 7764937
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:03:05+00:00 2026-06-01T15:03:05+00:00

Starting Situation These two commands should be equivalent. jQuery(‘a’).filter(‘:contains(about)’); and jQuery.find(‘a’).filter(‘:contains(about)’); Problem In fact,

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Starting Situation

These two commands should be equivalent.

jQuery('a').filter(':contains(about)');

and

jQuery.find('a').filter(':contains(about)');

Problem

In fact, the first command performs well, whereas the second throws the following exception:

TypeError: :contains(about) is not a function

Why ist that? Shouldn’t jQuery('a') and jQuery.find('a') return the same object? If not, what’s the difference?

Explanation

I am dynamically building a JQuery command chain (part of a JQuery Java Wrapper which is used in my project Abmash). Therefore, i prefer a chain of methods like jQuery.find('a').filter(':contains(about)').

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T15:03:06+00:00Added an answer on June 1, 2026 at 3:03 pm

    jQuery.find('a') returns a array (Array.filter() takes a function as argument.)

    jQuery('a') returns a jQuery-array-like-Object

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