Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 741505
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T08:38:24+00:00 2026-05-14T08:38:24+00:00

startTrains() -> TotalDist = 100, Trains = [trainA,trainB ], PID = spawn(fun() -> train(1,length(Trains))

  • 0
startTrains() ->
    TotalDist = 100,
    Trains = [trainA,trainB ],
    PID = spawn(fun() -> 
            train(1,length(Trains)) end),
    [ PID ! {self(),TrainData,TotalDist} || TrainData <- Trains],
    receive
    {_From, Mesg} ->
        error_logger:info_msg("~n Mesg ~p ~n",[Mesg])
            after 10500 ->
        refresh
    end.

so, I created Two Processes named trainA, trainB. I want to increment these process by 5 till it gets 100. I made different processes to make each of the train (process) increments its position parallely. But I was surprised to get the output sequentially i.e process trainA ends then process trainB starts. But I want to increment themselves at simultaneously.
I want to run processes like this


trainA 10 trainB 0
trainA 15 trainB 5
....
trainA 100 trainB 100 

but I m getting


trainA 0
....
trainA 90
trainA 95
trainA 100
trainA ends

trainB 0
trainB 5
trainB 10
.....
trainB 100

How to make the processes run parallel/simultaneously? Hope you get my Q’s. Please help me.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T08:38:24+00:00Added an answer on May 14, 2026 at 8:38 am

    You spawn only one process initialized by function train/2. Your presented code is incomplete so I can only guess but I think your code is wrong because you have only one train process. For inspiration:

    -module(trains).
    
    -export([startTrains/0]).
    
    startTrains() ->
      TotalDist = 100,
      Names = [trainA,trainB ],
      Self = self(),
      Trains = [spawn_link(fun() -> 
              train(Name, Self) end) || Name <- Names],
      [ Train ! {start, Self, 0, TotalDist} || Train <- Trains],
      ok = collectResults(Names).
    
    collectResults([]) -> ok;
    collectResults(Trains) ->
      receive
        {stop, Name, Pos, Length} ->
          io:format("~p stops at ~p (~p)~n", [Name, Pos, Length]),
          collectResults(Trains -- [Name]);
        Msg ->
          io:format("Supervisor received unexpected message ~p~n", [Msg]),
          collectResults(Trains)
      after 10500 -> timeout
      end.
    
    train(Name, Sup) ->
      receive
        {start, Sup, Pos, Length} -> run_train(Name, Sup, Pos, Length);
        Msg ->
          io:format("~p received unexpected message ~p~n", [Name, Msg]),
          train(Name, Sup)
      end.
    
    run_train(Name, Sup, Pos, Length)
      when Pos < Length ->
        receive after 500 ->
            NewPos = Pos + 5,
            io:format("~p ~p~n", [Name, Pos]),
            run_train(Name, Sup, NewPos, Length)
        end;
    run_train(Name, Sup, Pos, Length) ->
      Sup ! {stop, Name, Pos, Length}.
    

    But if I would think it seriously I should look to gen_fsm and OTP principles. But in your current stage keep play with erlang primitives to take better feeling first.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

No related questions found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.