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Home/ Questions/Q 7701593
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Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T23:01:30+00:00 2026-05-31T23:01:30+00:00

static void main(args){ System.in.withReader { def input = it.readLine() for(def i = 0; i

  • 0
static void main(args){

        System.in.withReader {
            def input = it.readLine()
            for(def i = 0; i < input; i++){
                println i
            }
        }

    }

The source code..simple one I guess but dont know why it is printing till 48..here is the output if the argument supplied is 1.

0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
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29
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41
42
43
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46
47
48

what could be the problem?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T23:01:31+00:00Added an answer on May 31, 2026 at 11:01 pm

    Tartar is right, the solution is to change

    def input = it.readLine()
    

    To

    def input = Integer.parseInt( it.readLine() )
    

    Or (more Groovy)

    def input = it.readLine().toInteger()
    

    (the reason it is using the ASCII value of 1 is that groovy will convert single char strings to their ASCII value if you try to coerce them into an int… It has been argued that this is confusing, and it may change in future versions of groovy, but for now it remains for backward compatibility reasons)

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