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Home/ Questions/Q 735537
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:30:07+00:00 2026-05-14T07:30:07+00:00

std::map<int,int> mapy; ++mapy[5]; Is it safe to assume that mapy[5] will always be 1?

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std::map<int,int> mapy;
++mapy[5];

Is it safe to assume that mapy[5] will always be 1? I mean, will mapy[5] always get the default value of 0 before ‘++’, even if not explicitly declared, as in my code?

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:30:07+00:00Added an answer on May 14, 2026 at 7:30 am

    As soon as you access the map with the [] operator, if the key doesn’t exist it gets added. The int gets "value initialization" invoked – so it will get a value of 0.

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