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Home/ Questions/Q 8189803
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T03:24:20+00:00 2026-06-07T03:24:20+00:00

still fairly new to ruby, and wrote this very simple recursive function. def test(input)

  • 0

still fairly new to ruby, and wrote this very simple recursive function.

  def test(input)
    if input != 0
        test(input-1)
    end
    if input == 0
        return true
    end
  end
  puts test(5)

from my Java knowledge I know this should return true but it doesn’t. It seems like the return statement doesn’t actually break out of the method. how do I fix this? thanks

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  1. Editorial Team
    Editorial Team
    2026-06-07T03:24:22+00:00Added an answer on June 7, 2026 at 3:24 am

    If you watch carefully you will see that the method does in fact return, but it only unwinds the stack one level and continues executing code in the caller.

    The problem is that you forgot a return:

    def test(input)
        if input != 0
            return test(input-1)
        end
        if input == 0
            return true
        end
    end
    puts test(5)
    

    With this fix, the result is as expected:

    true
    

    See it working online: ideone

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