Question

Still in learning mode and may be the following question is a really dumb but I dont have any idea why it is happening..

#include<stdio.h>
int main()
    {
      /* code to accept string and then a character from stdin */
         char str[20], inp;
         /*take string from stdin */
         printf("string:\n");
         scanf("%s",str);
         fflush(stdin);
         /*input a character */
         printf("char:\n");
         scanf("%c",&inp);/* code does not reach this point and exits */

    }

As mentioned in the comment, after I input the string , for eg. ‘strng’ the code just exits after printing char: but it does not wait for me input the character. As per my understanding, I have given the size of the array large enough to store the string and if the string entered is smaller than the size of the str array, the compiler will automatically add null character at the end of the string and proceed further. Am I missing something or is there a mistake in my code. Please suggest.

Thanks.

Answer 1

Put a space before the %c in the second scanf like this:

scanf(" %c",&inp)

And as stated by others fflush is defined only for output streams.