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Home/ Questions/Q 1101873
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:05:52+00:00 2026-05-17T01:05:52+00:00

Still trying to learn the basic of jquery so in the weekend I started

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Still trying to learn the basic of jquery so in the weekend I started looking on simple rewriting of links in greasemonkey. The script is working but it’s not looping.
It just take the url from the first .img and and write it into all the other .img instead of getting the each link and write it into the same element. Not sure if it made any sense but take a look at the script and I’m sure you understand. 🙂

   function rewrite() {
   $.each($(".img"),function(){
   var a=$("a img[src*='/SAN/']").attr('src');
   $("a img[src*='/SAN/']").parent().attr('href','http://somesite.com/'+a);
});
}
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  1. Editorial Team
    Editorial Team
    2026-05-17T01:05:53+00:00Added an answer on May 17, 2026 at 1:05 am

    It looks like this is what you’re after:

    function rewrite() {
      $("a img[src*='/SAN/']").each(function() {
        $(this).parent().attr("href", 'http://somesite.com/'+this.src);
      });
    }
    

    This loops through each image and sets the parent <a> href property based on the src of the current image you’re looping over, using this inside that .each() loop is the key here. Otherwise .attr() gets the attribute from the first element it matches, rather than the current element you’re looping over.

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