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Home/ Questions/Q 8880503
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T20:10:40+00:00 2026-06-14T20:10:40+00:00

str.find() always returns -1 if not found. Can I write an expression instead of

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str.find() always returns -1 if not found.
Can I write an expression instead of str.find() and return None if not found?

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  1. Editorial Team
    Editorial Team
    2026-06-14T20:10:41+00:00Added an answer on June 14, 2026 at 8:10 pm

    If I sum up, you want something which:

    • Is an expression
    • Evaluates to None when not found
    • Evaluates to the index when found
    • Does not use a ternary (so that Python 2.4 can handle it)

    The only solution I could come up with which satisfies all requirements is this weird thing:

    (lambda x: x and x - 1)((str.find(substr) + 1) or None)
    

    For example:

    >>> (lambda x: x and x - 1)(('abcd'.find('b') + 1) or None)
    1
    >>> (lambda x: x and x - 1)(('abcd'.find('_') + 1) or None)
    >>>
    

    I don’t have a Python 2.4 install to test one, so I can only hope it works.

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