Question

str1 = "M Rahim (C)(W): 61(97)S A Hasan: 51(68)"
str2 = "R Taylor (C): 76(160)B Watling: 16(26)"

puts format(str1) #=> "M Rahim (C)(W): 61(97)\nS A Hasan: 51(68)"
puts format(str2) #=> "R Taylor (C): 76(160)\nB Watling: 16(26)"

for getting these output what I need to do in format() function. I am not much familiar with regular expressions

Answer 1

This might do the trick but it is hard to know with such a limited sample:

def format(s)
  s.sub(/\A(.*?:\s*\d+\(\d+\))/) { $1 + "\n" }
end

The main thing that looks for is ': 61(97)' and ': 76(160)' or, generally, a colon followed by zero or more whitespace characters followed by a number followed by a number within parentheses.

If you don’t know how many entries are on each line then you can use scan to extract them and join to put them back together:

def format(s)
  s.scan(/.*?:\s*\d+\(\d+\)/).join("\n")
end

for example:

>> s = str1 + str2
=> "M Rahim (C)(W): 61(97)S A Hasan: 51(68)R Taylor (C): 76(160)B Watling: 16(26)"
>> s.scan(/.*?:\s*\d+\(\d+\)/).join("\n")
=> "M Rahim (C)(W): 61(97)\nS A Hasan: 51(68)\nR Taylor (C): 76(160)\nB Watling: 16(26)"