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Home/ Questions/Q 7633729
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T06:58:04+00:00 2026-05-31T06:58:04+00:00

Straight into business: I have code looking roughly like this: char* assemble(int param) {

  • 0

Straight into business: I have code looking roughly like this:

char* assemble(int param)
{
    char* result = "Foo" << doSomething(param) << "bar";
    return result;
}

Now what I get is:

error: invalid operands of types ‘const char [4]’ and ‘char*’ to binary ‘operator<<’

Edit:
doSomething returns a char*.

So, how do I concatenate these two?

Additional info:
Compiler: g++ 4.4.5 on GNU/Linux 2.6.32-5-amd64

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T06:58:05+00:00Added an answer on May 31, 2026 at 6:58 am

    "Foo" and "Bar" are literals, they don’t have the insertion (<<) operator.

    you instead need to use std::string if you want to do basic concatenation:

    std::string assemble(int param)
    {
        std::string s = "Foo";
        s += doSomething(param); //assumes doSomething returns char* or std::string
        s += "bar";
        return s;
    }
    
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