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Home/ Questions/Q 7020587
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:20:15+00:00 2026-05-27T23:20:15+00:00

Straight to the code: class ArithmeticExpressionParser<T> : Parser { T num1, num2; /* ………

  • 0

Straight to the code:

class ArithmeticExpressionParser<T> : Parser
{
    T num1, num2;

    /* ......... */

    void ParseNumber()
    {
        string temp = String.Empty;

        while (char.IsDigit(PeekNextToken()))
        {
            GetNextToken();
            temp += Token;
        }

        num1 = T.Parse(temp);  // <<< the problem
    }

Basically, if I was using an int or double I would have just use int.Parse etc. I’ve tried casting num1 = (T)temp; , which didn’t work. How can I do this without having to write a custom string to T function?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:20:16+00:00Added an answer on May 27, 2026 at 11:20 pm
    class ArithmeticExpressionParser<T> : Parser where T : IConvertible
    {
        T num1, num2;
    
        /* ......... */
    
        void ParseNumber()
        {
            string temp = String.Empty;
    
            while (char.IsDigit(PeekNextToken()))
            {
                GetNextToken();
                temp += Token;
            }
    
            //num1 = T.Parse(temp);  // <<< the problem
            num1 = (T)Convert.ChangeType( temp, typeof( T ) );
        }
    }
    

    This assumes that all the types you are converting implement IConvertible, which will allow you to place a generic constraint on your parser class. If not all types are convertible, you will need to switch conversion methods based on the type (messy).

    If necessary, you can also implement IConvertible on your own types. There are many methods to implement, but if you are dealing with primitive values it usually doesn’t take too long to implement.

    http://msdn.microsoft.com/en-us/library/system.iconvertible.aspx

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