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Home/ Questions/Q 7398219
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T03:50:37+00:00 2026-05-29T03:50:37+00:00

Straight to the code: #define PRO_SIGNAL( func, param ) (*func)(param) void PRO_SIGNAL( paint[0], Pro_Window*

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Straight to the code:

#define PRO_SIGNAL( func, param ) (*func)(param)
void PRO_SIGNAL( paint[0], Pro_Window* );

signal->paint = realloc( signal->paint, sizeof( void (*)(Pro_Window*) ) * signal->paint_count );

The Error:

error: incompatible types when assigning to type 'void (*[])(struct Pro_Window *)' from type 'void *'|
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T03:50:37+00:00Added an answer on May 29, 2026 at 3:50 am

    It appears that you are assigning to an array not a pointer.

    From your output error message:

    'void (*[])(struct Pro_Window *)' from type 'void *'| 
    

    Note the [] in there (and it certainly isn’t a lambda!) rather than a *

    If this is an “extendable” struct you need to realloc the entire struct not just the array member.

    By the way, a tip: if realloc fails it returns a NULL pointer and if you assign it to the variable that was being realloc’ed, the original memory it was pointing to will be lost forever. So always realloc into a temp first, check the value, and then assign back to the original pointer if it worked.

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