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Home/ Questions/Q 444533
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T21:16:48+00:00 2026-05-12T21:16:48+00:00

// stream from file. ifstream file; int main (int argc, char * argv[]) {

  • 0
// stream from file.
ifstream file;

int main (int argc, char * argv[]) {

// get argument passed from command line
// This is file name
if (argc != 2 ) {
    cout << "use:  ./executable <filename>";

}else {
    //cout << "You are using filename: " << argv[1];

    // start the file stream
    file (argv[1]);
}

Is there any reason why file(argv[1]) would be giving an error? Can I have a ifstream as a global variable?

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  1. Editorial Team
    Editorial Team
    2026-05-12T21:16:49+00:00Added an answer on May 12, 2026 at 9:16 pm

    You’re trying to call the ifstream‘s () operator (which doesn’t exist), when you should be using file.open(argv[1]).

    Besides that, there’s nothing illegal about having a global ifstream.

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