Question

string = "#1x#2#3#4#5#6#";

    String array[] = string.split("#");
    for(int count=0;count<=6;count++){
        // String temp = array[count];
        String temp1 = array[count].substring(0,1).trim();//here temp1="1"
        //  String temp1 = "1"; //this is possible 
        log (Integer.parseInt( temp1));// i cant convert the array which is populated by split("delimiter") why ??
    }

Here’s the array:

array[]=("1","2","3","4","5","6"}

I can convert the the String array[] into integer when i am declaring this as normal String array but when i am using split and populating the String array here in this example .

I am ready to explain if you can’t understand too. Help me out in this?
The Error is

Exception in thread "main" java.lang.NumberFormatException: For input string: ""
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)

My question is Integer.parseInt(string_array_populated_by_split_method[count]) is throwing Exception

Here the return value is a string “1” i.e Integer.parseInt(“1”).. this “1” is generated by split() method

Thanks in Advance.

Answer 1

You are doing a

substring(0, 0)

which is returning "", and "" cannot be converted to int. If you want to get the first character, you need to do:

substring(0, 1)

Then why you are trimming a single character, I don’t know…

Edit

Your new problem is:

The fact that your String starts with a # means that the first value in your array will be a "", and this one is causing problem. What you can do is testing that the String length is superior that 0:

for(String current : array){
    if(current.length() > 0) {  
        String temp1 = current.substring(0,1);
        log (Integer.parseInt( temp1));
    }
} 

Or you could also make sure that your String at the beginning isn’t starting with a #.