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Home/ Questions/Q 6033497
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T05:29:29+00:00 2026-05-23T05:29:29+00:00

string actionName = Users; [HttpGet] [ActionName(actionName)] public ActionResult GetMe() { } …gives: An object

  • 0
string actionName = "Users";

[HttpGet]
[ActionName(actionName)]
public ActionResult GetMe()
{

}

…gives: An object reference is required for the non-static field, method, or property

That was just a test though, is there a way to do this? If so, I could re-use the same Controller and possibly create new URIs on the fly… right?

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  1. Editorial Team
    Editorial Team
    2026-05-23T05:29:30+00:00Added an answer on May 23, 2026 at 5:29 am

    Assuming you have the following controller:

    public class HomeController : Controller
    {
        public ActionResult Index()
        {
            return View();
        }
    }
    

    you could write a custom route handler:

    public class MyRouteHander : IRouteHandler
    {
        public IHttpHandler GetHttpHandler(RequestContext requestContext)
        {
            var rd = requestContext.RouteData;
            var action = rd.GetRequiredString("action");
            var controller = rd.GetRequiredString("controller");
            if (string.Equals(action, "users", StringComparison.OrdinalIgnoreCase) &&
                string.Equals(controller, "home", StringComparison.OrdinalIgnoreCase))
            {
                // The action name is dynamic
                string actionName = "Index";
                requestContext.RouteData.Values["action"] = actionName;
            }
            return new MvcHandler(requestContext);
        }
    }
    

    Finally associate the custom route handler in your route definitions:

    routes.MapRoute(
        "Default",
        "{controller}/{action}/{id}",
        new { controller = "Home", action = "Index", id = UrlParameter.Optional }
    ).RouteHandler = new MyRouteHander();
    

    Now if you request /home/users it’s the Index action of the Home controller that will be served.

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