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String construct got space for the data by doing
new char[strlen(cp)+1];
Since there are only strlen(cp)characters in the string, what is the extra byte for?
For the special
'\0'char which indicates end of string.(Remember, C-style strings are null-terminated arrays).
Additional helpful notes:
strlendoes not count the'\0'(That’s why you need this extra byte).strcpydoes copy the'\0'.char str[7] = "String";– Adds'\0'by itself.char str[] = {'S','t','r','i','n','g'}– Does not add'\0'.char str[7] = {'S','t','r','i','n','g'}– Will add'\0'.