Question

String date="12/20/20102";
        SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy");           
             Date today;
            try {
                today = df.parse(date.trim());
              Log.e("Error", "Correct");
            } catch (java.text.ParseException e) {
                // TODO Auto-generated catch block
                Log.e("Error", "InCorrect");
            } 

I am not able to get this corrected. I always get this converted and if I give an incorrect date string also it not catching in the exception.

Please help me.

Answer 1

Your string input is :

String date="12/20/20102";
SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy"); 

Two mistakes:

1. String date = “12/20/20122“; // it shoud be “12/20/2012“

2. Your String input is in MM/dd/yyyy format and you trying to parse in dd/MM/yyyy format. Change your string input format (20/12/2012) OR change formatter to (MM/dd/yyyy).

EDIT

Here is sample code for validating user input date in dd/MM/yyyy format.

String str = txt.getText().toString();

            try{
            String tmp[] = str.split("/");
            int day = Integer.parseInt(tmp[0]);
            int month = Integer.parseInt(tmp[1]);
            int year = Integer.parseInt(tmp[2]);

                if(!(day > 31) && !(month > 12) && (tmp[2].length() == 4) )
                {
                    // Verified date....
                }
                else
                {
                    Toast.makeText(getBaseContext(), "Please enter date in correct format. (dd/MM/yyy)", Toast.LENGTH_SHORT).show();
                }
            }
            catch (Exception e) {
                Toast.makeText(getBaseContext(), e.toString(), Toast.LENGTH_SHORT).show();
            }

Note: Leap year and February month logic is not implemented.

Full validation with all conditions available here.
http://www.mkyong.com/regular-expressions/how-to-validate-date-with-regular-expression/

And don’t forget to accept this if it helps you.

Thanks…